Java WebServices API getNetworkAdapter
Posted: 16. Jan 2013, 19:49
Hi
I'm using the Java webservices api to build out a set of commands for Java Virtualbox. One of the things that I am stuck on is disabling a Network Adapter on a particular Guest VM. Basically virtually unplugging the network cable.
When I used VboxManage.exe, I could call the command VBoxManage.exe controlvm sGuestVMName setlinkstate[adapter ID] off
Now that I'm using the Java WebServices API this type of command is not so easy to define... At least for me...
Here's my code...
I've scoured the web and I can't find any easy examples of how to do this...
Any insight on this would help me immensely..
Thanks
Bill
I'm using the Java webservices api to build out a set of commands for Java Virtualbox. One of the things that I am stuck on is disabling a Network Adapter on a particular Guest VM. Basically virtually unplugging the network cable.
When I used VboxManage.exe, I could call the command VBoxManage.exe controlvm sGuestVMName setlinkstate[adapter ID] off
Now that I'm using the Java WebServices API this type of command is not so easy to define... At least for me...
Here's my code...
Code: Select all
public void setLinkState(VirtualBoxManager oJavaVirtualBoxMgr, IVirtualBox oVirtualBoxInstance, String sVMName,String linkState, int iAdapterID){
ISession oSession = null;
IConsole oConsole = null;
IMachine oMachine = null;
INetworkAdapter oNetwork = null;
try{
oMachine = oVirtualBoxInstance.findMachine(sVMName);
oSession = oJavaVirtualBoxMgr.getSessionObject();
oMachine.lockMachine(oSession, LockType.Shared);
oNetwork = oMachine.getNetworkAdapter();[b] <---- Here is where I'm stuck... Trying to define the iAdapterID which is an int to the long that is required for Slot???? Not sure[/b]
if (linkState.equals("On")){
oNetwork.setCableConnected(true);[b] <---- Also I'm not sure if this works the way I hope it does.. Meaning will it work like "setlinkstate" in VboxManage.exe[/b]
}else{
oNetwork.setCableConnected(false);
}
oSession.unlockMachine();
}catch (VBoxException e)
{
e.printStackTrace();
}
}
Any insight on this would help me immensely..
Thanks
Bill